x^(2/5)-x^(1/5)-2=0

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Solution for x^(2/5)-x^(1/5)-2=0 equation: 


x in (-oo:+oo)

x^(2/5)-x^(1/5)-2 = 0

t_1 = x^(1/5)

1*t_1^2-1*t_1^1-2 = 0

t_1^2-t_1-2 = 0

DELTA = (-1)^2-(-2*1*4)

DELTA = 9

DELTA > 0

t_1 = (9^(1/2)+1)/(1*2) or t_1 = (1-9^(1/2))/(1*2)

t_1 = 2 or t_1 = -1

t_1 = -1

x^(1/5)+1 = 0

1*x^(1/5) = -1 // : 1

x^(1/5) = -1

( -1 < 0 i 1/5 in (0:1) ) => x naleu017Cy do O

t_1 = 2

x^(1/5)-2 = 0

1*x^(1/5) = 2 // : 1

x^(1/5) = 2

x^(1/5) = 2 // ^ 5

x = 32

x = 32

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